BECC-107 Solved Assignment
For July 2023 and January 2024 Admission Cycles
Answer the following Descriptive Category Questions in about 500 words each. Each question carries 20 \mathbf{2 0} marks. Word limit does not apply in the case of numerical questions.
- (a) Calculate mean, median and mode from the following data.
Class Interval | Frequency |
3 | |
7 | |
22 | |
60 | |
85 | |
32 | |
8 |
(b) Calculate the coefficient of variation from the data given above.
2. Bring out the distinction between sample survey and census. Describe the steps you would follow in collecting data though a sample survey. Prepare a small questionnaire for collection of income and expenditure levels of households.
2. Bring out the distinction between sample survey and census. Describe the steps you would follow in collecting data though a sample survey. Prepare a small questionnaire for collection of income and expenditure levels of households.
Assignment II
Answer the following Middle Category Questions in about 250 words each. Each question carries 10 \mathbf{1 0} marks. Word limit does not apply in the case of numerical questions.
-
a) The probability that Rajesh will score more than 90 marks in class test is 0.75 . What is the probability that Rajesh will secure more than 90 marks in three out of four class tests?
b) Bring out the major properties of binomial distribution. Mention certain important uses of this distribution. -
a) Fit a straight line
(Y=a+bX) (Y=a+b X) to the following data. Compare the estimated values of the dependent variable with its actual values.
X | 5 | 8 | 10 | 12 | 13 | 15 | 17 | 16 |
Y | 8 | 12 | 14 | 10 | 13 | 16 | 14 | 17 |
b) Define correlation coefficient. What are its properties?
- What is a life table? Explain its uses and limitations.
Assignment III
Answer the following Short Category Questions. Each question carries 15 \mathbf{1 5} marks.
- Write short notes on the following:
(a) Bayes’ theorem of probability
(b) Age specific birth and death rates
(c) Measurement of Skewness - Differentiate between the following:
(a) Simple random sampling and Stratified random sampling
(b) Type I and Type II errors in hypothesis testing
(c) Estimator and Estimate
Expert Answer
BECC-107 Solved Assignment
For July 2023 and January 2024 Admission Cycles
Question:-01(a)
Calculate mean, median and mode from the following data.
Class Interval | Frequency |
3-4 | 3 |
4-5 | 7 |
5-6 | 22 |
6-7 | 60 |
7-8 | 85 |
8-9 | 32 |
9-10 | 8 |
Answer:
To find Median Class
= = value of ((n)/(2))^(“th “) \left(\frac{n}{2}\right)^{\text {th }} observation
= = value of ((217)/(2))^(“th “) \left(\frac{217}{2}\right)^{\text {th }} observation
= = value of 108^(“th “) 108^{\text {th }} observation
From the column of cumulative frequencycf c f , we find that the 108^(“th “) 108^{\text {th }} observation lies in the class 7-8 7-8 .
:. \therefore The median class is 7-8 7-8 .
Now,
:.L= \therefore L= lower boundary point of median class =7 =7
:.n= \therefore n= Total frequency =217 =217
:.cf= \therefore c f= Cumulative frequency of the class preceding the median class =92 =92
:.f= \therefore f= Frequency of the median class =85 =85
:.c= \therefore c= class length of median class =1 =1
MedianM=L+((n)/(2)-cf)/(f)*c M=L+\frac{\frac{n}{2}-c f}{f} \cdot c
From the column of cumulative frequency
Now,
Median
To find Mode Class
Here, maximum frequency is 85 .
:. \therefore The mode class is 7-8 7-8 .
:.L= \therefore L= lower boundary point of mode class =7 =7
:.f_(1)= \therefore f_1= frequency of the mode class =85 =85
:.f_(0)= \therefore f_0= frequency of the preceding class =60 =60
:.f_(2)= \therefore f_2= frequency of the succedding class =32 =32
:.c= \therefore c= class length of mode class =1 =1
Z=L+((f_(1)-f_(0))/(2*f_(1)-f_(0)-f_(2)))*c Z=L+\left(\frac{f_1-f_0}{2 \cdot f_1-f_0-f_2}\right) \cdot c
=7+((85-60)/(2*85-60-32))*1 =7+\left(\frac{85-60}{2 \cdot 85-60-32}\right) \cdot 1
=7+((25)/(78))*1 =7+\left(\frac{25}{78}\right) \cdot 1
=7+0.3205 =7+0.3205
=7.3205 =7.3205
Here, maximum frequency is 85 .
Question:-01(b)
Calculate the coefficient of variation from the data given above.
Answer:
Population Standard deviation sigma=sqrt((sum f*x^(2)-((sum f*x)^(2))/(n))/(n)) \sigma=\sqrt{\frac{\sum f \cdot x^2-\frac{\left(\sum f \cdot x\right)^2}{n}}{n}}
Question:-02
Bring out the distinction between sample survey and census. Describe the steps you would follow in collecting data though a sample survey. Prepare a small questionnaire for collection of income and expenditure levels of households.
Answer:
Distinction Between Sample Survey and Census
Census and sample surveys are two key methods used for collecting data from a population. The primary distinction lies in the scope of the data collection.
1. Census:
-
Definition: A census is a method of data collection in which every unit or member of a population is surveyed. It aims to cover the entire population, leaving no one out.
-
Characteristics:
- Complete enumeration: Every individual or unit in the population is included.
- Accuracy: Since it covers the entire population, the data obtained can be highly accurate, assuming no measurement errors occur.
- Costly and Time-Consuming: Due to its large scale, conducting a census requires significant time, financial resources, and personnel.
- Infrequent: Censuses are typically conducted at long intervals (e.g., every 10 years) due to their complexity.
-
Example: National population census where every household in the country is surveyed to obtain demographic data.
2. Sample Survey:
-
Definition: A sample survey collects data from a subset of the population rather than the entire population. The subset, or sample, is chosen to be representative of the population.
-
Characteristics:
- Partial enumeration: Only a sample, not the entire population, is surveyed.
- Cost-effective: Sample surveys are generally less expensive and quicker to conduct than censuses.
- Potential for Sampling Error: Since not everyone is surveyed, the results may have some degree of sampling error, though this can be minimized with good sampling techniques.
- Frequent: Sample surveys can be conducted more frequently due to their lower cost and faster execution.
-
Example: A survey of 1,000 households to determine average household income across a country.
Steps in Collecting Data Through a Sample Survey
To conduct a sample survey efficiently, the following steps should be taken:
1. Define the Objectives of the Survey:
- Clearly identify the purpose of the survey and the kind of information you want to collect. For instance, you might aim to assess the income and expenditure patterns of households in a particular region.
2. Define the Population:
- Determine the target population for your survey. This could be the entire population of a city, a specific age group, or households with certain characteristics.
3. Select a Sampling Method:
- Choose an appropriate sampling method to ensure that the sample is representative of the population. Common methods include:
- Simple random sampling: Every individual in the population has an equal chance of being selected.
- Stratified sampling: The population is divided into strata (e.g., income levels), and a random sample is taken from each stratum.
- Cluster sampling: The population is divided into clusters (e.g., neighborhoods), and entire clusters are randomly selected.
4. Determine the Sample Size:
- Decide how many individuals or units to survey. The sample size should be large enough to be representative but small enough to be manageable within available resources.
5. Design the Questionnaire:
- Create a well-structured questionnaire that collects the necessary data. The questions should be clear, concise, and relevant to the objectives of the survey.
6. Conduct a Pilot Survey:
- Test the questionnaire and survey process on a small sample to identify any potential issues or misunderstandings.
7. Collect the Data:
- Administer the survey to the selected sample. This can be done through face-to-face interviews, telephone interviews, mailed questionnaires, or online surveys.
8. Process and Analyze the Data:
- After collecting the data, process it (e.g., coding responses, checking for errors) and analyze it using statistical methods to draw conclusions about the population.
9. Report the Findings:
- Present the findings in a clear and understandable manner, typically in the form of a report or presentation.
Sample Questionnaire for Collecting Income and Expenditure Levels of Households
Title: Household Income and Expenditure Survey
Instructions: Please answer the following questions honestly and to the best of your knowledge. All information provided will be kept confidential and used only for research purposes.
Section A: Household Information
- Number of Household Members: _______
- Location of Household (City, Town, Village): ____________________
- Main Source of Household Income (Tick one):
- [ ] Salaried Employment
- [ ] Self-Employment
- [ ] Agriculture
- [ ] Pension
- [ ] Other: ____________________
Section B: Household Income
-
What is your household’s total monthly income?
- [ ] Less than $500
- [ ] $500 – $999
- [ ] $1,000 – $1,499
- [ ] $1,500 – $1,999
- [ ] $2,000 and above
-
Does your household receive any additional income from the following sources? (Tick all that apply)
- [ ] Rental income
- [ ] Government assistance
- [ ] Interest or dividends
- [ ] Remittances from family abroad
- [ ] Other: ____________________
Section C: Household Expenditure
-
What is your household’s total monthly expenditure?
- [ ] Less than $500
- [ ] $500 – $999
- [ ] $1,000 – $1,499
- [ ] $1,500 – $1,999
- [ ] $2,000 and above
-
Please estimate your household’s monthly expenditure on the following categories:
Category | Monthly Expenditure ($) |
---|---|
Food and groceries | ___________________________ |
Housing (rent/mortgage) | ___________________________ |
Utilities (electricity, water, gas) | ___________________________ |
Education | ___________________________ |
Healthcare | ___________________________ |
Transportation | ___________________________ |
Entertainment and leisure | ___________________________ |
Other | ___________________________ |
Section D: Savings and Investments
-
Does your household save any portion of its income?
- [ ] Yes
- [ ] No
-
If yes, what percentage of your household’s income is saved monthly?
- [ ] Less than 5%
- [ ] 5% – 10%
- [ ] 11% – 15%
- [ ] More than 15%
-
Does your household invest in any of the following? (Tick all that apply)
- [ ] Real estate
- [ ] Stocks or bonds
- [ ] Mutual funds
- [ ] Pension funds
- [ ] Other: ____________________
End of Questionnaire
Thank you for your participation!
Thank you for your participation!
This questionnaire is designed to gather basic information on household income and expenditure levels, which can be used for analyzing consumption patterns, savings rates, and investment behavior across households.
Assignment II
Question:-03(a)
The probability that Rajesh will score more than 90 marks in a class test is 0.75. What is the probability that Rajesh will secure more than 90 marks in three out of four class tests?
Answer:
To solve this problem, we can model it using a binomial distribution because we are dealing with a series of independent events (class tests), each of which has two possible outcomes: Rajesh scores more than 90 marks (success) or Rajesh scores 90 or fewer marks (failure).
Given Data:
- The probability that Rajesh scores more than 90 marks in a single test,
p p , is0.75 0.75 . - The number of class tests,
n n , is 4. - We are asked to find the probability that Rajesh scores more than 90 marks in exactly 3 out of 4 tests, which means
k=3 k = 3 .
Binomial Probability Formula:
The probability of getting exactly k k successes in n n independent trials is given by the binomial probability formula:
Where:
((n)/(k)) \binom{n}{k} is the binomial coefficient, representing the number of ways to choosek k successes fromn n trials.p p is the probability of success in a single trial.1-p 1 – p is the probability of failure in a single trial.X X is the number of successes.
Step-by-Step Calculation:
-
n=4 n = 4 ,k=3 k = 3 , andp=0.75 p = 0.75 . -
The binomial coefficient
((4)/(3)) \binom{4}{3} is calculated as:
- Substituting the values into the binomial probability formula:
- Calculate the powers of 0.75 and 0.25:
- Perform the multiplication:
Conclusion:
The probability that Rajesh will secure more than 90 marks in exactly 3 out of 4 class tests is 0.4219 (rounded to four decimal places).
Question:-03(b)
Bring out the major properties of binomial distribution. Mention certain important uses of this distribution.
Answer:
Major Properties of Binomial Distribution
The binomial distribution is one of the most commonly used probability distributions in statistics. It describes the number of successes in a fixed number of independent trials, where each trial has two possible outcomes: success or failure.
Here are the major properties of the binomial distribution:
-
Fixed Number of Trials (n):
- The binomial distribution is based on a fixed number of trials, denoted by
n n . Each trial is independent of the others, and the number of trials is predetermined.
- The binomial distribution is based on a fixed number of trials, denoted by
-
Two Possible Outcomes:
- Each trial has exactly two possible outcomes: success (with probability
p p ) and failure (with probability1-p 1 – p ). These outcomes are mutually exclusive and collectively exhaustive.
- Each trial has exactly two possible outcomes: success (with probability
-
Constant Probability of Success:
- The probability of success, denoted by
p p , remains constant for each trial. Similarly, the probability of failure remains1-p 1 – p throughout the trials.
- The probability of success, denoted by
-
Independence of Trials:
- The trials are independent, meaning the outcome of one trial does not affect the outcome of any other trial.
-
Discrete Distribution:
- The binomial distribution is discrete, meaning it deals with outcomes that are countable, such as the number of successes in a series of trials.
-
Probability Mass Function (PMF):
- The probability of observing exactly
k k successes inn n trials is given by the binomial probability mass function:
P(X=k)=((n)/(k))*p^(k)*(1-p)^(n-k) P(X = k) = \binom{n}{k} \cdot p^k \cdot (1 – p)^{n – k} Where:((n)/(k)) \binom{n}{k} is the binomial coefficient, representing the number of ways to choosek k successes fromn n trials.p p is the probability of success on each trial.1-p 1 – p is the probability of failure on each trial.
- The probability of observing exactly
-
Mean and Variance:
- The mean
mu \mu of a binomial distribution is given by:
mu=n*p \mu = n \cdot p - The variance
sigma^(2) \sigma^2 of a binomial distribution is given by:
sigma^(2)=n*p*(1-p) \sigma^2 = n \cdot p \cdot (1 – p) - The mean
-
Symmetry and Shape:
- The shape of the binomial distribution depends on the value of
p p :- If
p=0.5 p = 0.5 , the distribution is symmetric. - If
p < 0.5 p < 0.5 , the distribution is skewed to the right (positively skewed). - If
p > 0.5 p > 0.5 , the distribution is skewed to the left (negatively skewed).
- If
- The shape of the binomial distribution depends on the value of
Important Uses of Binomial Distribution
The binomial distribution has several important uses in various fields of study. Some of its key applications include:
-
Quality Control and Manufacturing:
- The binomial distribution is used to model the number of defective items in a batch or the number of successful outcomes in a series of quality control tests. For example, it can be used to calculate the probability that a certain number of products out of a sample are defective.
-
Medical Research:
- In clinical trials, the binomial distribution can be used to model the probability of a certain number of patients responding to a treatment (success) versus not responding (failure). This helps in analyzing the effectiveness of treatments or drugs.
-
Survey Research and Polling:
- Binomial distribution is useful in analyzing survey results, where the outcome of interest might be a simple yes/no answer. For example, it can be used to calculate the probability that a certain percentage of respondents will support a particular candidate or policy.
-
Reliability Testing:
- In reliability engineering, the binomial distribution can be used to model the probability of a certain number of components in a system failing within a specified period, assuming each component has the same probability of failure.
-
Genetics:
- In genetics, the binomial distribution is used to predict the number of offspring with a certain trait in a given number of trials (e.g., the probability that a certain number of offspring will inherit a particular gene).
-
Marketing and Sales:
- The binomial distribution is used to model the number of successful sales calls or responses in a given number of attempts, helping to analyze the effectiveness of sales strategies or marketing campaigns.
-
Finance and Insurance:
- Binomial distribution can be used in finance to model the number of successful investments or in insurance to model the number of claims filed out of a certain number of policies.
Conclusion
The binomial distribution is a versatile and widely used probability distribution in various fields. Its properties—such as a fixed number of trials, constant probability of success, and independence of trials—make it particularly useful for modeling scenarios with binary outcomes (success or failure). Its applications range from quality control to clinical trials, finance, and marketing, helping researchers and decision-makers analyze and predict the likelihood of specific outcomes.
Question:-04(a)
Fit a straight line Y=a+bX Y = a + bX to the following data. Compare the estimated values of the dependent variable with its actual values.
X | 5 | 8 | 10 | 12 | 13 | 15 | 17 | 16 |
Y | 8 | 12 | 14 | 10 | 13 | 16 | 14 | 17 |
Answer:
Straight line equation is y=a+bx y=a+b x .
The normal equations are
The normal equations are
The values are calculated using the following table
5 | 8 | 25 | 40 |
8 | 12 | 64 | 96 |
10 | 14 | 100 | 140 |
12 | 10 | 144 | 120 |
13 | 13 | 169 | 169 |
15 | 16 | 225 | 240 |
17 | 14 | 289 | 238 |
16 | 17 | 256 | 272 |
— | — | — | — |