Free MCS-208 Solved Assignment | July 2025 and January 2026 | Data Structures and Algorithms | IGNOU

MCS-208: Data Structures and Algorithms | IGNOU BCA Solved Assignment 2025-26

📚 MCS-208: DATA STRUCTURES AND ALGORITHMS

IGNOU BCA Solved Assignment | July 2025 & January 2026 Sessions

Course Information

Course Code MCS-208
Programme BCA_NEW (3rd Semester)
Submission Date July 2025: 31st October 2025
Jan 2026: 30th April 2026
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MCS-208: Data Structures and Algorithms - Complete Solutions
1. For each of the Singly Linked List, Circularly Singly Linked List, Doubly Linked List, Circularly Doubly Linked List, write one application that is exclusively suitable for that list. For example, X may be an application for whose implementation, only Circularly Singly Linked List is suitable and others are not suitable. Justify your answer.
20 marks

Each type of linked list has unique characteristics that make it particularly suitable for certain applications. Understanding these distinctions helps us choose the most appropriate data structure for specific problem domains.

1. Singly Linked List - Web Browser History Implementation

A singly linked list is exclusively suitable for implementing a simplified web browser history where users can only navigate backward through their browsing history (like a "Back" button functionality without "Forward").

Structure:

struct HistoryNode { string url; string pageTitle; HistoryNode* previous; };

Why Singly Linked List is Ideal:

  • Memory Efficiency: Only one pointer per node reduces memory overhead compared to doubly linked lists
  • Sequential Access Pattern: Users typically navigate backward sequentially through their history
  • Simple Implementation: Easy to implement with minimal complexity
  • Dynamic Size: History can grow indefinitely without pre-allocation

Why Other Lists Are Not Suitable:

  • Circular Lists: Would create infinite loops in history navigation
  • Doubly Linked List: Unnecessary overhead since forward navigation isn't needed in this simple implementation

2. Circularly Singly Linked List - Round-Robin CPU Scheduling

A circularly singly linked list is exclusively suitable for implementing Round-Robin CPU scheduling in operating systems where processes are executed in a circular fashion with equal time slices.

Structure:

struct ProcessNode { int processID; int burstTime; int priority; ProcessNode* next; // Points to next process, last points to first };

Why Circularly Singly Linked List is Ideal:

  • Infinite Cycling: Automatically returns to the first process after the last one
  • No NULL Checks: Eliminates need for special handling of list boundaries
  • Fair Scheduling: Ensures every process gets equal opportunity
  • Continuous Operation: Scheduler can run indefinitely without restart logic

Why Other Lists Are Not Suitable:

  • Singly Linked List: Would require manual reset to beginning after reaching end
  • Doubly Linked Lists: Backward navigation unnecessary, adds memory overhead
  • Circular Doubly: Overkill for simple forward-only scheduling

3. Doubly Linked List - Text Editor with Cursor Movement

A doubly linked list is exclusively suitable for implementing a sophisticated text editor where each character is a node and cursor can move bidirectionally with insertion/deletion at any position.

Structure:

struct CharNode { char character; CharNode* next; CharNode* prev; };

Why Doubly Linked List is Ideal:

  • Bidirectional Navigation: Cursor can move left and right efficiently
  • Efficient Insertion/Deletion: Can insert or delete at cursor position in O(1) time
  • No Boundary Issues: Can handle beginning and end of text seamlessly
  • Undo/Redo Implementation: Can track changes bidirectionally

Why Other Lists Are Not Suitable:

  • Singly Linked List: Cannot move cursor backward efficiently
  • Circular Lists: Would connect end of text to beginning, creating unwanted behavior
  • Arrays: Insertion/deletion in middle requires shifting all subsequent elements

4. Circularly Doubly Linked List - Advanced Music Player Playlist

A circularly doubly linked list is exclusively suitable for implementing an advanced music player playlist that supports shuffle mode, repeat mode, and seamless bidirectional navigation through an infinite playlist loop.

Structure:

struct SongNode { string songTitle; string artist; int duration; SongNode* next; SongNode* prev; // Last song's next points to first song // First song's prev points to last song };

Why Circularly Doubly Linked List is Ideal:

  • Infinite Playback: Automatically loops from last song to first and vice versa
  • Bidirectional Navigation: Users can go forward or backward through playlist
  • Seamless Boundaries: No special handling needed at playlist edges
  • Shuffle Implementation: Can randomly jump to any song and still maintain circular navigation
  • Repeat Modes: Supports repeat-one, repeat-all, and shuffle modes naturally

Advanced Features Enabled:

  • Previous song from first song goes to last song
  • Next song from last song goes to first song
  • Efficient insertion of new songs anywhere in playlist
  • Support for collaborative playlists with real-time updates

Why Other Lists Are Not Suitable:

  • Singly Linked List: Cannot navigate backward to previous songs
  • Circularly Singly: Cannot implement "previous song" functionality
  • Doubly Linked List: Requires special handling at playlist boundaries
  • Arrays: Fixed size, inefficient insertion/deletion of songs

Comparative Analysis

Each linked list type offers unique advantages:

Memory Efficiency: Singly < Circularly Singly < Doubly < Circularly Doubly

Navigation Flexibility: Singly < Circularly Singly < Doubly < Circularly Doubly

Implementation Complexity: Singly < Doubly < Circularly Singly < Circularly Doubly

Implementation Considerations

When choosing between these data structures, consider:

  • Memory Constraints: Use simpler structures when memory is limited
  • Access Patterns: Match structure to how data will be accessed
  • Boundary Conditions: Circular structures eliminate special boundary handling
  • Bidirectional Needs: Use doubly linked when backward navigation is essential

These specific applications demonstrate how each linked list variant has exclusive advantages that make it the optimal choice for particular problem domains, justifying their existence in the programmer's toolkit.

2. We can test whether a node 'm' is a proper ancestor of a node 'n' by testing whether 'm' precedes 'n' in X-order but follows 'n' in Y-order, where X and Y are chosen from {pre, post, in}. Determine all those pairs X and Y for which this statement holds.
20 marks

This question explores the relationship between different tree traversal orders and how they can be used to determine ancestor-descendant relationships in binary trees. Understanding this concept requires deep knowledge of tree traversal algorithms and their ordering properties.

Understanding Tree Traversal Orders

Before analyzing the ancestor-descendant relationship, let's review the three tree traversal methods:

Preorder Traversal (Pre): Visit Root → Left Subtree → Right Subtree

Inorder Traversal (In): Visit Left Subtree → Root → Right Subtree

Postorder Traversal (Post): Visit Left Subtree → Right Subtree → Root

Proper Ancestor Definition

Node 'm' is a proper ancestor of node 'n' if:

  • There exists a path from 'm' to 'n' in the tree
  • 'm' is not the same as 'n' (proper ancestor excludes the node itself)
  • 'm' appears before 'n' on the path from root to 'n'

Example Tree for Analysis

Let's consider this binary tree for our analysis:

A / \ B C / \ \ D E F / G

Traversal Results:

  • Preorder: A, B, D, G, E, C, F
  • Inorder: G, D, B, E, A, C, F
  • Postorder: G, D, E, B, F, C, A

Analysis of All Possible Pairs

Case 1: X = Preorder, Y = Postorder

Condition: 'm' precedes 'n' in preorder AND 'm' follows 'n' in postorder

Analysis:

  • In preorder, ancestors are always visited before their descendants
  • In postorder, ancestors are always visited after their descendants
  • This perfectly captures the ancestor-descendant relationship

Example: A is ancestor of G

  • Preorder: A (position 1) precedes G (position 4) ✓
  • Postorder: A (position 7) follows G (position 1) ✓

Verification: B is ancestor of D

  • Preorder: B (position 2) precedes D (position 3) ✓
  • Postorder: B (position 4) follows D (position 2) ✓

✓ This pair WORKS

Case 2: X = Preorder, Y = Inorder

Condition: 'm' precedes 'n' in preorder AND 'm' follows 'n' in inorder

Analysis:

This doesn't consistently work because inorder placement depends on whether the ancestor is in the left or right subtree relative to the descendant.

Counter-example: A is ancestor of E

  • Preorder: A (position 1) precedes E (position 5) ✓
  • Inorder: A (position 5) follows E (position 4) ✓

But consider: A is ancestor of D

  • Preorder: A (position 1) precedes D (position 3) ✓
  • Inorder: A (position 5) precedes D (position 2) ✗

✗ This pair DOESN'T WORK

Case 3: X = Inorder, Y = Preorder

Condition: 'm' precedes 'n' in inorder AND 'm' follows 'n' in preorder

Analysis:

This is the reverse of Case 2 and suffers from similar issues. The inorder position of an ancestor relative to its descendant varies based on tree structure.

Counter-example: A is ancestor of D

  • Inorder: A (position 5) follows D (position 2) ✗

✗ This pair DOESN'T WORK

Case 4: X = Inorder, Y = Postorder

Condition: 'm' precedes 'n' in inorder AND 'm' follows 'n' in postorder

Analysis:

The inorder traversal doesn't provide consistent ancestor-descendant ordering, making this combination unreliable.

Counter-example: A is ancestor of B

  • Inorder: A (position 5) follows B (position 3) ✗

✗ This pair DOESN'T WORK

Case 5: X = Postorder, Y = Preorder

Condition: 'm' precedes 'n' in postorder AND 'm' follows 'n' in preorder

Analysis:

This is the reverse of Case 1. In postorder, descendants appear before ancestors, while in preorder, ancestors appear before descendants.

Counter-example: A is ancestor of G

  • Postorder: A (position 7) follows G (position 1) ✗ (We need A to precede G)

✗ This pair DOESN'T WORK

Case 6: X = Postorder, Y = Inorder

Condition: 'm' precedes 'n' in postorder AND 'm' follows 'n' in inorder

Analysis:

Similar issues as previous cases involving inorder traversal - inconsistent ancestor-descendant relationships.

✗ This pair DOESN'T WORK

Mathematical Proof for X = Preorder, Y = Postorder

For any node 'm' that is a proper ancestor of node 'n':

In Preorder:

  • The subtree rooted at 'm' contains 'n'
  • Preorder visits 'm' before exploring its subtrees
  • Therefore, 'm' appears before 'n' in preorder traversal

In Postorder:

  • Postorder explores all subtrees before visiting the root
  • Since 'n' is in a subtree of 'm', 'n' is visited before 'm'
  • Therefore, 'm' appears after 'n' in postorder traversal

Conclusion

Answer: Only the pair (X = Preorder, Y = Postorder) satisfies the given condition.

This makes intuitive sense because:

  • Preorder naturally visits ancestors before descendants
  • Postorder naturally visits descendants before ancestors
  • These complementary properties create a reliable test for ancestor-descendant relationships
3. Define Left Leaning Red Black trees. Explain their properties. What are the advantages of Left Leaning Red Black trees over Red Black trees?
20 marks

Left Leaning Red Black Trees (LLRB) represent an elegant simplification of the traditional Red Black Tree data structure. They were introduced by Robert Sedgewick as a way to maintain the performance benefits of Red Black Trees while significantly reducing implementation complexity.

Definition of Left Leaning Red Black Trees

A Left Leaning Red Black Tree is a binary search tree where nodes are colored either red or black, with specific structural constraints that ensure the tree remains approximately balanced. The key innovation is the "left leaning" property that restricts red links to only appear as left links, creating a more uniform structure.

Properties of Left Leaning Red Black Trees

1. Fundamental Color Properties

  • Node Coloring: Every node is either red or black
  • Root Property: The root node is always black
  • Leaf Property: All leaf nodes (NIL nodes) are considered black
  • Red Node Constraint: Red nodes cannot have red children (no two consecutive red nodes on any path)

2. Left Leaning Specific Properties

  • Red Links Are Left Links: All red links in the tree lean to the left (red nodes are always left children)
  • No Right Red Links: There are never any right-leaning red links
  • No Node Has Two Red Links: A node cannot have both left and right red children simultaneously
  • Perfect Black Balance: Every path from root to leaf contains the same number of black nodes

3. Structural Properties

  • Binary Search Tree Property: For any node, all values in left subtree are smaller, all values in right subtree are larger
  • Balanced Height: The longest path is at most twice as long as the shortest path
  • Logarithmic Operations: Search, insert, and delete operations are guaranteed O(log n)

Visual Representation

In LLRB trees, red links are typically drawn as horizontal connections leaning left:

Valid LLRB structure: B(black) / \ R(red) B(black) / \ B(black) B(black) Invalid in LLRB (right-leaning red): B(black) / \ B(black) R(red) \ B(black)

Implementation Considerations

Node Structure

class LLRBNode { int key; int value; LLRBNode left, right; boolean color; // true = red, false = black int size; // size of subtree }

Key Operations

Rotation Operations:

  • Rotate Left: Converts right-leaning red link to left-leaning
  • Rotate Right: Converts left-leaning red link to right-leaning
  • Color Flip: Changes colors of node and both children

Invariant Maintenance:

  • After each insertion, apply rotations and color flips to maintain LLRB properties
  • Check for right-leaning red links and rotate left
  • Check for consecutive red links and rotate right
  • Check for node with two red children and flip colors

Advantages of LLRB Trees over Traditional Red Black Trees

1. Implementation Simplicity

Reduced Code Complexity:

  • LLRB insertion requires only about 10 lines of code after the recursive insertion
  • Traditional RB trees require complex case analysis with multiple rotation scenarios
  • Fewer special cases to handle during insertion and deletion
  • Uniform left-leaning constraint eliminates mirror-image cases

Example Insertion Pseudocode:

// LLRB Insertion (simplified) function insert(node, key, value) { if (node == null) return new RedNode(key, value); // Standard BST insertion if (key < node.key) node.left = insert(node.left, key, value); else if (key > node.key) node.right = insert(node.right, key, value); else node.value = value; // LLRB balancing (only 3 operations!) if (isRed(node.right) && !isRed(node.left)) node = rotateLeft(node); if (isRed(node.left) && isRed(node.left.left)) node = rotateRight(node); if (isRed(node.left) && isRed(node.right)) flipColors(node); return node; }

2. Maintenance Advantages

  • Easier Debugging: Simpler structure makes tree visualization and debugging more straightforward
  • Fewer Bugs: Reduced complexity leads to fewer implementation errors
  • Better Code Readability: More maintainable codebase
  • Easier Testing: Fewer edge cases to test thoroughly

3. Educational Benefits

  • Learning Curve: Easier to understand and teach
  • Conceptual Clarity: Cleaner abstraction of balanced tree concepts
  • Implementation Practice: Good stepping stone to understanding more complex balanced trees

4. Performance Characteristics

Comparable Performance:

  • Same O(log n) time complexity for all operations as traditional RB trees
  • Similar space complexity
  • Slightly fewer rotations on average due to simpler rebalancing
  • Better cache performance due to more predictable structure

Practical Benefits:

  • Faster development time due to simpler implementation
  • Reduced likelihood of implementation bugs
  • Easier integration into existing systems

5. Algorithmic Elegance

  • Uniform Rules: Single set of transformation rules applies to all cases
  • Symmetric Reduction: Eliminates the need to handle symmetric cases separately
  • Natural Correspondence: Direct relationship with 2-3 trees makes analysis easier

Relationship to 2-3 Trees

LLRB trees have a natural correspondence with 2-3 trees:

  • Each red link represents a 3-node in the corresponding 2-3 tree
  • Black nodes represent 2-nodes
  • This correspondence makes the balanced property obvious and provable

Limitations

While LLRB trees offer many advantages, they do have some limitations:

  • Deletion Complexity: Deletion is still somewhat complex, though simpler than traditional RB trees
  • Memory Overhead: Still requires color bit storage for each node
  • Not Universal: Some specific applications might benefit from the flexibility of traditional RB trees

Conclusion

Left Leaning Red Black Trees represent an excellent balance between performance and simplicity. They maintain all the performance guarantees of traditional Red Black Trees while offering significantly simpler implementation and maintenance. For most practical applications, LLRB trees are the preferred choice due to their elegance and reduced complexity, making them an excellent example of how algorithmic innovation can improve both theoretical understanding and practical implementation.

4. What is minimum spanning tree? Write the algorithms for finding the minimum spanning tree. Trace the algorithms for the given graph.
20 marks

A Minimum Spanning Tree (MST) is a fundamental concept in graph theory with wide-ranging applications in network design, clustering, and optimization problems. Understanding MST algorithms is crucial for solving real-world connectivity problems efficiently.

Definition of Minimum Spanning Tree

A Minimum Spanning Tree of a connected, undirected, weighted graph is a spanning tree that connects all vertices with the minimum possible total edge weight. Key properties include:

  • Spanning: Connects all vertices in the graph
  • Tree: Has exactly V-1 edges for V vertices (no cycles)
  • Minimum: Has the smallest possible sum of edge weights
  • Uniqueness: May not be unique if multiple edges have the same weight

Applications of MST

  • Network design (telecommunications, computer networks)
  • Circuit design and VLSI layout
  • Cluster analysis and data mining
  • Transportation and logistics planning
  • Image segmentation and computer vision

Kruskal's Algorithm

Kruskal's algorithm uses a greedy approach by sorting edges by weight and adding them to the MST if they don't create a cycle.

Algorithm Steps:

  1. Sort all edges in non-decreasing order of weight
  2. Initialize MST as empty set
  3. For each edge in sorted order:
    • If edge connects two different components, add to MST
    • If edge would create cycle, skip it
  4. Continue until MST has V-1 edges

Pseudocode:

function KruskalMST(graph G): MST = empty set sort all edges by weight in ascending order initialize disjoint set for all vertices for each edge (u,v) with weight w in sorted order: if find(u) != find(v): // u and v in different components add edge (u,v) to MST union(u, v) // merge components if MST has V-1 edges: break return MST

Prim's Algorithm

Prim's algorithm grows the MST one vertex at a time by always adding the minimum weight edge connecting the current MST to a new vertex.

Algorithm Steps:

  1. Start with arbitrary vertex as initial MST
  2. Maintain priority queue of edges from MST vertices to non-MST vertices
  3. Repeatedly:
    • Extract minimum weight edge from priority queue
    • Add the edge and new vertex to MST
    • Update priority queue with edges from new vertex
  4. Continue until all vertices are in MST

Pseudocode:

function PrimMST(graph G, start vertex s): MST = empty set visited = {s} priority_queue = edges from s to all neighbors while priority_queue not empty and |visited| < V: edge (u,v) = extract_min(priority_queue) if v not in visited: add edge (u,v) to MST add v to visited for each neighbor w of v: if w not in visited: add edge (v,w) to priority_queue return MST

Example Graph for Tracing

Let's trace both algorithms on this weighted graph:

Vertices: A, B, C, D, E Edges with weights: A-B: 4 A-C: 2 B-C: 1 B-D: 5 C-D: 8 C-E: 10 D-E: 2 B-E: 3 Graph representation: A /|\ 4 2 | / | | B---C | |1 8\|/ 5 \|E | 10|\ D-----+ 2 E

Tracing Kruskal's Algorithm

Step 1: Sort edges by weight

Sorted edges: 1. B-C: 1 2. A-C: 2 3. D-E: 2 4. B-E: 3 5. A-B: 4 6. B-D: 5 7. C-D: 8 8. C-E: 10

Step 2: Process edges using Union-Find

Initial: Each vertex is its own component Components: {A}, {B}, {C}, {D}, {E} Edge B-C (weight 1): - B and C in different components → Add to MST - Components: {A}, {B,C}, {D}, {E} - MST: {B-C: 1} Edge A-C (weight 2): - A and C in different components → Add to MST - Components: {A,B,C}, {D}, {E} - MST: {B-C: 1, A-C: 2} Edge D-E (weight 2): - D and E in different components → Add to MST - Components: {A,B,C}, {D,E} - MST: {B-C: 1, A-C: 2, D-E: 2} Edge B-E (weight 3): - B in component {A,B,C}, E in component {D,E} - Different components → Add to MST - Components: {A,B,C,D,E} - MST: {B-C: 1, A-C: 2, D-E: 2, B-E: 3} MST Complete! Total weight: 1 + 2 + 2 + 3 = 8

Tracing Prim's Algorithm

Starting from vertex A:

Step 1: Start with A - Visited: {A} - Priority Queue: [A-C:2, A-B:4] - MST: {} Step 2: Process A-C (weight 2) - Add C to MST via edge A-C - Visited: {A, C} - Add C's edges: [A-B:4, C-B:1, C-D:8, C-E:10] - Priority Queue: [C-B:1, A-B:4, C-D:8, C-E:10] - MST: {A-C: 2} Step 3: Process C-B (weight 1) - Add B to MST via edge C-B - Visited: {A, C, B} - Add B's edges: [A-B:4, B-D:5, B-E:3, C-D:8, C-E:10] - Priority Queue: [B-E:3, A-B:4, B-D:5, C-D:8, C-E:10] - MST: {A-C: 2, C-B: 1} Step 4: Process B-E (weight 3) - Add E to MST via edge B-E - Visited: {A, C, B, E} - Add E's edges: [A-B:4, B-D:5, E-D:2, C-D:8, C-E:10] - Priority Queue: [E-D:2, A-B:4, B-D:5, C-D:8, C-E:10] - MST: {A-C: 2, C-B: 1, B-E: 3} Step 5: Process E-D (weight 2) - Add D to MST via edge E-D - Visited: {A, C, B, E, D} - All vertices visited - MST: {A-C: 2, C-B: 1, B-E: 3, E-D: 2} Final MST weight: 2 + 1 + 3 + 2 = 8

Comparison of Results

Both algorithms produce MST with total weight 8, but different edge selections:

  • Kruskal's MST: {B-C: 1, A-C: 2, D-E: 2, B-E: 3}
  • Prim's MST: {A-C: 2, C-B: 1, B-E: 3, E-D: 2}
  • Note: Same edges, different representation order

Algorithm Comparison

Kruskal's | Prim's Time Complexity: O(E log E) | O(E log V) with binary heap | O(E + V log V) with Fibonacci heap Space Complexity: O(V) | O(V) Best for: Sparse graphs | Dense graphs Data Structure: Union-Find | Priority Queue Edge Selection: Global minimum | Local minimum from MST

Implementation Considerations

Kruskal's Algorithm:

  • Requires efficient Union-Find data structure
  • Better for sparse graphs where E << V²
  • Edge-focused approach
  • Natural for parallel processing

Prim's Algorithm:

  • Requires efficient priority queue
  • Better for dense graphs where E ≈ V²
  • Vertex-focused approach
  • Can start from any vertex

Properties of MST

  • Cut Property: For any cut, the minimum weight edge crossing the cut is in some MST
  • Cycle Property: For any cycle, the maximum weight edge in the cycle is not in any MST
  • Uniqueness: MST is unique if all edge weights are distinct
  • Optimality: Both Kruskal's and Prim's algorithms always produce optimal MST

Understanding these MST algorithms and their properties is essential for solving complex network optimization problems efficiently in various domains.

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