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IGNOU BPHCT-131 Solved Assignment 2024 | B.Sc (G) CBCS
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IGNOU BPHCT-131 Assignment Question Paper 2024
bphct-131-solved-assignment-2024–qp-b0a87631-f2d0-400e-939b-0b99078c2d98
- a) Determine the projection of
vec(A)+2 vec(B) \overrightarrow{\mathbf{A}}+\mathbf{2} \overrightarrow{\mathbf{B}} onvec(B) \overrightarrow{\mathbf{B}} wherevec(A)=2 hat(i)- hat(j)+3 hat(k) \overrightarrow{\mathbf{A}}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+3 \hat{\mathbf{k}} andvec(B)=- hat(i)+4 hat(j)+ hat(k) \overrightarrow{\mathbf{B}}=-\hat{\mathbf{i}}+4 \hat{\mathbf{j}}+\hat{\mathbf{k}} .
- Solve the following ordinary differential equations:
a)(4x^(3)y^(3)+(1)/(x))dx+(3x^(4)y^(2)-(1)/(y))dy=0 \left(4 x^3 y^3+\frac{1}{x}\right) d x+\left(3 x^4 y^2-\frac{1}{y}\right) d y=0 .
- a) A mass of
10kg 10 \mathrm{~kg} , is released from rest on an incline that makes a30^(@) 30^{\circ} angle with the horizontal. In2s 2 \mathrm{~s} , the mass is observed to have moved a distance of4m 4 \mathrm{~m} . What is the coefficient of kinetic friction between the mass and the surface of the incline? Draw the free body diagram.
4. a) A cylindrical drum has a radius of
- a) The oscillation of a simple harmonic oscillator is described by the equation
BPHCT-131 Sample Solution 2024
bphct-131-solved-assignment-2024–ss-8e24e610-06c9-4b43-84f6-a5bf6ef5ab5c
- a) Determine the projection of
vec(A)+2 vec(B) \overrightarrow{\mathbf{A}}+\mathbf{2} \overrightarrow{\mathbf{B}} onvec(B) \overrightarrow{\mathbf{B}} wherevec(A)=2 hat(i)- hat(j)+3 hat(k) \overrightarrow{\mathbf{A}}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+3 \hat{\mathbf{k}} andvec(B)=- hat(i)+4 hat(j)+ hat(k) \overrightarrow{\mathbf{B}}=-\hat{\mathbf{i}}+4 \hat{\mathbf{j}}+\hat{\mathbf{k}} .
- For
t hat(i) t\hat{\mathbf{i}} , the derivative is(dt)/(dt) hat(i)=1 hat(i) \frac{dt}{dt}\hat{\mathbf{i}} = 1\hat{\mathbf{i}} . - For
e^(t^(2)) hat(j) e^{t^2}\hat{\mathbf{j}} , using the chain rule, the derivative is(d)/(dt)(e^(t^(2))) hat(j)=2te^(t^(2)) hat(j) \frac{d}{dt}(e^{t^2})\hat{\mathbf{j}} = 2te^{t^2}\hat{\mathbf{j}} . - For
sin(2t) hat(k) \sin(2t)\hat{\mathbf{k}} , the derivative is(d)/(dt)(sin(2t)) hat(k)=2cos(2t) hat(k) \frac{d}{dt}(\sin(2t))\hat{\mathbf{k}} = 2\cos(2t)\hat{\mathbf{k}} .
- For
hat(i) \hat{\mathbf{i}} component:(1)/(5.5901) \frac{1}{5.5901} - For
hat(j) \hat{\mathbf{j}} component:(2e)/(5.5901) \frac{2e}{5.5901} - For
hat(k) \hat{\mathbf{k}} component:(2cos(2))/(5.5901) \frac{2\cos(2)}{5.5901}
hat(i) \hat{\mathbf{i}} component:(1)/(5.5901)~~0.1789 \frac{1}{5.5901} \approx 0.1789 hat(j) \hat{\mathbf{j}} component:(2e)/(5.5901)~~0.9802 \frac{2e}{5.5901} \approx 0.9802 hat(k) \hat{\mathbf{k}} component:(2cos(2))/(5.5901)~~-0.7554 \frac{2\cos(2)}{5.5901} \approx -0.7554
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